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Sunday, September 20, 2015

Problems on Trains for Competitive Exams - Shortcuts, Tips and Tricks

Rule 1: When two trains are moving in opposite directions, then relative speed will be the addition of their individual speeds.

Rule 2: When two trains are moving in same direction, then relative speed will be the subtraction of their individual speeds.

Rule 3: On passing a platform by a certain train the net distance traveled is the sum of length of train and the length of platform both.

Rule 4: When a train passes through a pole or person standing, net distance traveled to pass is the length of the train

Ex 1. A train 120 m long is running at the speed of 54 km /hr. Find the time taken it to pass a man standing near the railway track.

Solution : speed of train = [54 * ( 5 / 18 ) ] = 15 m / sec

length of train = 120 m , So required time :

Ex 2. A train is moving at a speed of 54 km / hr. If the length of the train is 100 meters, how long will it take to cross a railway platform 110 meters long ?

Solution : speed of train = [54 * ( 5 / 18 ) ] = 15 m / sec

Distance covered in passing the platform = 100 + 110 = 210 m

Ex 3. Two trains 125 m and 100 m in length respectively are running in opposite directions, one at the rate of 50 km / hr and the other at the rate of 40 km /hr. At what time they will clear each other from the moment they meet ?

Solution : Relative speed of trains = (50 + 40) km / hr = [90 * ( 5 / 18 ) ] = 25 m / sec

Total length to be travelled = 125 + 100 = 225 m

Ex 4. Two trains 110 m and 100 m in length respectively are running in same directions, one at the rate of 100 km / hr and the other at the rate of 64 km / hr. At what time faster train will clear other train from the moment they meet ?

Solution : Since trains are running in same direction, so relative speed = 100-64 = 36 km / hr = [ 36 * ( 5 / 18 )] = 10 m / sec

Total length to be travelled = 110 + 100 = 210 m

Ex 5. A train 125 m in length, moves at a speed of 82 km / hr , In what time the train will cross a boy who is walking at 8 km / hr in opposite direction ?

Solution : Relative speed = 82+8 = 90 km / hr = [ 90 * ( 5 / 18 )] = 25 m / sec

Ex 6. A train passes a standing pole on the platform in 5 seconds and passes the platform completely in 20 seconds. If the length of the platform is 225 meters. Then find the length of the train ?

Solution : Let the length of the train is x meter

So speed of train =( x / 5 ) m / sec

Also speed of train = ( 225 + x ) / 20 m/sec

Ex 7. Two trains of length 115 m and 110 m respectively run on parallel rails. When running in the same direction the faster train passes the slower one in 25 seconds, but when they are running in opposite directions with the same speeds as earlier, they pass each other in 5 seconds. Find the speed of each train ?

Solution :
Let the speed of trains be x m/sec and y m/sec espectively.

When they move in same direction their relative speed is : x - y

When they moves in opposite direction their relative speed is : x + y

On solving two equations x=27 m/s and y=18 m/sec

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Time and Work Problems for Competitive Exams - Shortcuts, Tips and Tricks

Rule 1: If A can do a piece of work in D days, then A's 1 day's work = 1/D

Rule 2: If A's work efficiency is 2 times as compared to B then
Ratio of work done by A and B is 2 :1
Ratio of times taken by A and B to finish a work = 1 : 2 (inverse ratio)

Ex 1. A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work ?

So both will finish the work in 6 days

Ex 2. If A and B together can do a job in x days and A alone can do the same job in y days, then how many days it taken by B to complete the same job ?

Rule 3: Let M1 person can do W1 work in D1 days with time T1 and M2 person can do W2 work in D2 days with time T2, then the relationship can be written as :

Ex 4. If 40 people can make 60 toys in 8 hrs, if 8 people leave the work, how many toys can make in 12 hrs ?

Solution : here M1= 40, D1= 8 hrs, W1= 60, M2= 32, D2 =12 hrs, W2= ?

Rule 4: If A, B and C can do a work in x, y and z days respectively then all of them working together can finish the work in :

Ex 5. A and B can do a piece of work in 12 days , B and C in 15 days and C and A can do in 20 days. How long would each take seperately to do the same work ?

A+B+C can do the work in 5*2= 10 days

Ex 6. If 3 men or 4 women can do a work in 43 days, how long will 7 men and 5 women take to comlete the work ?
Solution:
3 men can complete 1 / 43 of work in a day
1 man can complete 1 /(43*3) work in a day
4 women can complete 1/ 43 of work in a day
1 woman can complete 1 / (43*4) of the work in a day

So, 7 men and 5 women will complete the work in 12 days

Ex 7. Seven men can complete a work in 12 days. They started the work and after 5 days, two men left. In how many days will the work be completed by the remaning men ?
Soution :
7 men 1 day's work will be 1 / 12
1 man 1 day work will be 1 / (12*7) = 1 / 84
7 men 5 days work will be 5 / 12, so remaning work will be (1- 5/ 12) = 7 / 12
5 mens 1 day work will be 5 / 84

Ex 8. A man, a women and a boy can complete a job in 3, 4 and 12 days respectively. How many boys must assist 1 man and 1 woman to complete the job in 1/4 of a day ?
Solution :
1 man's + 1 woman's one day work = 1 / 3 + 1 / 4 = 7 / 12
work done by 1 man + 1 woman in 1 / 4 day = (7 / 12 )*( 1 / 4 )= 7 / 48
So the work remains=(1-7/48)= 41 / 48
Also work done by one boy in 1 / 4 day = (1 / 12 )*(1 / 4 ) = 1 / 48

Since 1 / 48 work is done by 1 boy in 1 / 4 days
So 41 / 48 work can be done by ( 41 / 48 ) * (48 / 1) = 41

Ex 9. 10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work.How many days will be required for one woman alone to complete the same work ?
Solution :
1 man's one day work = 1 / 100
( 10 men's + 15 women's ) 1 day work= 1 / 6
15 women's one days work = (1 / 6 )- ( 10 / 100 ) = 1 / 15
1 woman 1 day work = ( 1 / 15* 15 ) = 1 / 225

So one woman will complete the work in 225 days

Ex 10. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be :
Solution :
(6 men and 8 boys ) 1 day work = 1 / 10
Thie can be written as equeation form, let 1 man's one day work is M and one boy's one day work is B

6 M + 8 B = 1 / 10
Similarly 15 M + 20 B = 1 / 2 on solving M = 1 / 100, B = 1 / 200
Now ( 15 men + 20 boy ) 1 day's work = ( 15 / 100 )+ ( 20 / 100 ) = 1 / 4

So 15 men and 20 boys can do the work in 4 days.

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Pipes and Cisterns Problems for Competitive Exams - Shortcuts, Tips and Tricks

Inlet Pipe: It is a pipe connected with a tank or reservoir for filling.Outlet Pipe: It is a pipe connected with a tank and used for empties.

Rule 1: If a pipe can fill a tank in x hours, then the part filled in 1 hour = 1 / xRule 2: If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours, then the net part filled in 1 hour, when both the pipes are opened :

Time taken to fill the tank, when both the pipes are opened :

Rule 3: If a pipe can fill a tank in x hours and another fill the same tank in y hours, then the net part filled in 1 hr, when both pipes are opened:

So time to fill the tank will be :

Rule 4: If a pipe fills a tank in x hrs and another fills the same tank in y hrs, but a third empties the full tank in z hrs and all of them are opened together, the net part filled in 1 hr :

So time taken to fill the tank :

Ex 1. A tank is filled by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank ?Solution : Let Pipe A take x hours to fill the tank , then pipes B will take x / 2 hrs and pipe C will take x / 4 hours respectively.

Then part to be filled by all three pipes in 1 hrs will be :

Ex. Three pipes A, B and C can fill a tank in 6 hours. After working together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. Find the number of hours taken by C alone to fill the tank .Solution : Work done by A+B+C in 2 hours = 2 /6 = 1 / 3
So, work remaining = 1- ( 1/ 3 ) = 2 / 3
Now (A + B)'s 7 hour work = 2 / 3
( A + B )'s 1 hour work will be = 2 / 21

So C's 1 hour work will be = 1 hour work of (A+B+C) - 1 hour work of (A+B) = ( 1/ 6) - ( 2/ 21) = 1 / 14

So C alone can fill the tank in 14 hours

Ex 2. A cistern is normally filled in 8 hrs, but it takes four hrs longer to fill because of a leak in the bottom. If the cistern is full , how much time the leak will empty it ?Solution : Let the leak will empty the tank in x hrs.
Then part of cistern filled in 1 hr = ( 1 / 8 ) - ( 1 / x ) = x - 8 / 8x
So cistern will completely filled in 8x / x - 8

Ex 3. Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, Pipe A is turned off. What is the total time required to fill the tank ?Solution :Part of tank filled by A + B in 1 minute = ( 1 / 15 + 1 / 20 )
So tank filled by A + B in 4 minute = 4 ( 1 / 15 + 1 / 20 ) = 7 / 15
Part remaining = 1 - ( 7 / 15 ) = 8 / 15

1 / 20 part is filled by B in 1 minute

So, 8 / 15 part will be filled in = ( 20 / 1 )* ( 8 / 15 ) = 32 / 3 = 10 minutes 40 sec.

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SAIL Recruitment 2015 - Proficiency Training of Nurses at DSP Hospital - 50 Posts

Durgapur Steel Plant (DSP) Hospital is a 600 bedded multi-speciality hospital offering “Proficiency Training’ at DSP Hospital for qualified nurses. The Hospital invites eligible & interested qualified nurses for walk-in-interview to undertake the “Proficiency Training’ in DSP Hospital.

No. of Proficiency Trainee: 50

Upper Age Limit: 30 years for General, 33 years for OBC and 35 years for SC&ST As on 30.09.2015

Duration: 18 months.

Departments/ disciplines: ICU/NICU/BICU, Medicine, Surgery, Obs & Gyn, Paediatrics, Casualty, Orthopaedics, Chest & other associated areas.

Qualification:

a) B.Sc. (Nursing) / Diploma in General Nursing & Midwifery
b) Internship Certificate (if applicable), c) Certificate of Registration

Daily Working hours: 8 hrs shift - One day off per week

Honorarium: Stipend per month Rs.8000/-

Selection Process: Interview.

IMP Dates:

Last date of application: 30-09-2015.

IMP Links:
For official notification click here

Saturday, September 19, 2015

How to Prepare for a Competitive Exam?

In various countries and contexts, competitive written exams may test for reasoning ability; mathematical ability; reading and comprehension; writing ability; or the fundamental knowledge of a subject area. Interviews may test for knowledge of current events, general knowledge about the job or qualification one is applying for, the ability to give an account of one's past or future or talents, or the ability to say something sensible about a controversial or complicated issue.

Tips on Preparing for an Examination

1. Make Sure This Test Is for You

Before investing time in preparing for an exam, decide whether the work is worth it. Study the exam announcement and ask questions if necessary. Make sure you meet requirements like:

Educational level or experience needed to qualify to take the exam;
Percentage of marks, or grade point average;
Any maximum or minimum age limit that applies to your exam.

2. Go Back to Your Fundamentals

Once you know you qualify for your exam, your next step should be to decide how to brush up on fundamentals you haven't practiced recently. Depending on the test, this may be math fundamentals you last looked at in grade school, principles of grammar, or the fundamentals of your science or engineering discipline. Dig out your old textbooks and put them where you can see them.

3. Get Up to Date

If it's applicable to your test, as it is in the Indian Civil Service, work on your general knowledge and keep it updated. You will want to be ready to discuss the current events that affect the government, school, or bureaucracy you aim to join. If you don't already, take a daily look at news media on current events.

4. Consider Paying for Coaching ("Joint Coaching Institutes")

You don't have to pay a company or institute for competitive examination preparation. Many do well without such coaching. But the right test preparation agency can offer you:

counseling
reassurance
study materials with which to structure your time
Do investigate your chosen agency, and make sure it's not a scam; there are scammers out there.

5. Set Realistic Goals

Consider how much time you have until the test date, and how many other things you want to do in life—including fun things. Consider your level of ability, and the resources you have. Then set realistic, modest, and achievable goals and deadlines for finishing the different steps of your preparation. Manage your time so that your preparation includes each section of the test, with more time allotted to sections where you think you may be weaker.

6. Create a Support Group

Create a circle of friends who are interested in preparing for the same or similar examination. It will be very helpful in keeping up your morale. It will remind you that you are not struggling alone with an arbitrary, zero-sum world; many other people long for success, just like you do (see the numerous comments below). Though you may not all succeed the first time, you can at least support each other without hurting your own chances.

7. Be Positive

You should be positive and have faith in yourself. There is no guarantee that you will pass any exam on the first attempt, though there is no reason to assume you will fail. Be patient and support yourself over the long haul.

8. Take Mock Tests

It may not be difficult to answer all the questions on a test, but it's generally very difficult to answer them all in the allotted time. Obtain sample written tests from previous test occasions and time yourself as you take them. Understand how they are scored: whether it's to your advantage to guess at answers you aren't sure of, or whether you should skip these questions. Understand how fast you have to work to answer every question that has a chance of increasing your score. This kind of practice is very helpful.

9. Do Mock Interviews

Find sample interview questions (for example, in the library, in magazines, on the web) and write them down on cards, along with any other questions you can think of. Get your family or study group together, hand them the cards, and have them ask you the questions. It feels reassuring to be able to come up with something to say, even though it may not be perfect. Remember that it's quite likely you may be asked a question you don't know the answer to. If so, you can admit it; it's better not to guess or make something up. No one knows everything and there is no need to pretend to.

10. Go Easy on Yourself

Stay healthy while you prepare. Regular exercise and yoga boost your mental as well as physical strength. Do fun things during your study period, including on the night before the test. By that point, your preparation will be done--all except for showing up at the test, which is important in itself. Instead of trying to cram more information into your brain that night, why not watch a silly movie, or walk somewhere? Then, after arranging for your transportation and your breakfast, gathering up any documents or tools you need to bring, and laying out the clothes you plan to wear, go to sleep with a clear conscience. The result of the test will be out of your hands; you will have done all that you can do.

Via: [Hubpages]

See also:

Tips for Writing Essays for Competitive Exams

Friday, September 18, 2015

196 Jobs in Odisha Staff Selection Commission for Inspector of Supplies, Gram Panchayat Extension Officer and Progress Assistant

There are 196 vacancies in Odisha Staff Selection Commission(OSSC) for Inspector of Supplies, Gram Panchayat Extension Officer and Progress Assistant.

Post Details:

Inspector of Supplies: 45 Posts
Gram Panchayat Extension Officer: 59 Posts
Progress Assistant: 92 Posts

Age Limit:

Candidates age limit should between 21 to 32 years as on 01-01-2015.

Educational Qualification:

Candidates should have Bachelor Degree in any discipline from any recognized university & passed Odia equivalent to ME standard.

Selection Process:

Candidates will be selected based on written examination and viva-voce test.

Examination Fee:

Candidates should have to pay Rs. 100/- (No Fee for SC/ ST & PWD candidates).

How to Apply:

Eligible candidates can apply online through the website www.odishassc.in from 29-08-2015 to 28-09-2015.

Important Dates:

Starting Date to Apply Online: 29-08-2015.
Last Date to Apply Online: 28-09-2015.

IMP Links:

Other Jobs Updates:

370 Jobs in Odisha Staff Selection Commission for Sub Inspector, Sergeant Police & Officer Posts

There are 370 vacancies in Odisha Staff Selection Commission(OSSC) for Sub Inspector, Sergeant Police & Officer Posts.

Post Details:

1. Sub Inspector of Police: 327 Posts

ST: 74
SC: 53
SEBC: 37
UR: 163

2. Sergeant of Police: 24 Posts

ST: 05
SC: 04
SEBC: 03
UR: 12

3. Station Officer (Fire Service): 19 Posts

ST: 04
SC: 03
SEBC: 02
UR: 10

Age Limit:

Candidates age should be between 21-25 years as on 01-01-2015.

Educational Qualification:

Candidates should possess Graduation in any discipline from a recognized University for the post of Station Officer.

Selection Process:

Candidates will be selected based on Preliminary examination, Main examination & viva-voce.

Examination Fee:

Candidates have to pay Rs. 100/- (No fee for SC/ ST/ PwD candidates).

How to Apply:

Eligible candidates may apply online through the website www.odishassc.in from from 09-09-2015 to 09-10-2015.

IMP Dates:

Starting Date to Apply Online: 09-09-2015.
Last Date to Apply Online: 09-10-2015.